# how many bit strings of length 10 contain exactly four 1s

## how many bit strings of length 10 contain exactly four 1s ## How many bit strings of length 10 contain an equal number of 0s and 1s?

We subtract from the total number of bit strings of length 10 those that have only 0, 1, 2 or 3 1s. = 1024 − 1 − 10 − 45 − 120 = 848. d) an equal number of 0s and 1s? = 10!/(5!Apr 29, 2020

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## How many bit strings of length 10 contain more OS than 1s?

The answer thus is C(10, 3) = 10 . 9 . 8 / 3 . 2 . 1 = 120. How many bit strings of length 10 have more 0s than 1s? Decompose this problem into disjoint sub-problems; count each sub-problem: 6 0s & 4 1s: C(10, 6) = C(10, 4) = 10.9.8.7 / 4.3.2 = 210.

## How many bit strings of length 10 begin and end with a 1?

We are asked about 10 bits, but the first and the last bits are already chosen for us. Bits are either 1 or 0, so there are 2 choices per bit, and 8 bits to choose. Therefore, there are 28 = 256 bit strings of length ten that begin and end with a 1.

## How many 10 bit strings contain 6 or more 1’s?

How many 10-bit strings contain 6 or more 1's? Answer: (106)+(107)+(108)+(109)+(1010)=386 strings.Dec 20, 2020

## How many bit strings of length 10 contain an equal number of Os and 1s?

(d) An equal number of 0s and 1s in a string of length 10, means that there are five 0s and five 1s.

## How many bit strings of length 10 contain at least four 1s and at least three 0s?

1024 – 1 – 1 – 10 – 10 – 45 – 45 = 912. Therefore, 912 strings of length 10 contain at least three 1s and at least three 0s.

1s

## How many bit strings of length 10 contain at least 4 1s an equal number of 0s and 1s?

at most 4 1s

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## How many bits is a string of length 10?

From the question it is given that strings of length 10 contain at least three 1s and at least three 0s. The total length is = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024. 1024 – 1 – 1 – 10 – 10 – 45 – 45 = 912.

## How many six bit strings are there that begin and end with a 1 or start with 00?

How many six bits strings are there that begin and end with a 1, or start with 00? A string can not start with 0 and 1, so the sets are disjoint. Apply the sum rule: The number of strings that begin and end with 1 OR start with 00 is 24 + 24 = 16 + 16 = 32.

## How many bit strings of length 10 either starts with a 0 bit or end with the three bits 000 ‘?

Total: 2^5 x 2^1 x 1×2^2 = 32 x 2 x 4 = 256.Nov 7, 2015

## How many bit strings of length 10 begin and end with a 1?

We are asked about 10 bits, but the first and the last bits are already chosen for us. Bits are either 1 or 0, so there are 2 choices per bit, and 8 bits to choose. Therefore, there are 28 = 256 bit strings of length ten that begin and end with a 1.

## How many 9 bit strings contain 7 or more 1’s?

(a) How many 9-bit strings contain exactly seven 1's? (9 7 ) = 9 · 8 2 · 1 = 36.Apr 20, 2015

## How many bit strings of length 10 contain more OS than is?

From the question it is given that strings of length 10 contain at least three 1s and at least three 0s. The total length is = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024. 1024 – 1 – 1 – 10 – 10 – 45 – 45 = 912. Therefore, 912 strings of length 10 contain at least three 1s and at least three 0s.

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## How many 10 bit strings contain 6 or more 1’s?

How many 10-bit strings contain 6 or more 1's? Answer: (106)+(107)+(108)+(109)+(1010)=386 strings.Dec 20, 2020

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